(x-3)*(2x-5)=15+2x^2

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Solution for (x-3)*(2x-5)=15+2x^2 equation: 



(x-3)(2x-5)=15+2x^2

We move all terms to the left:

(x-3)(2x-5)-(15+2x^2)=0

We get rid of parentheses

-2x^2+(x-3)(2x-5)-15=0

We multiply parentheses ..

-2x^2+(+2x^2-5x-6x+15)-15=0

We get rid of parentheses

-2x^2+2x^2-5x-6x+15-15=0

We add all the numbers together, and all the variables

-11x=0

x=0/-11

x=0

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